VistaDB Connection

StarkStark Syria
edited June 2009 in FastReport .NET
Hi ,Have a good day ...

I want to connect Fast report to VistaDB .... ?

and I have two problems :

1 - I can't see the DataSource Of VistaDB , if I use the Smart tag of report1 in my VS IDE ....
but the Designer.exe .... work fine with it ( it's work as expected )


2 - I can't Understand this line of code :
FastReport.Utils.RegisteredObjects.AddConnection(typeof(VistaDBDataConnection));
What do you mean by VistaDBDataConnection is it VistaDB.Provider.VistaDBConnection ?

THINGS you need to know :
- I didn't install Fastreport on my mahcine from the msi file , I added fastreport.dll manually ... to VS toolbox
- I added the Fastreport.VistaDB.dll to my project references ....
- I deleted the fastreport.config , plus restart my VS .NET IDE about a 15 times ....


any help would be very appreciated

Kind regards ....

Comments

  • edited 8:25PM
    Hello,

    1) if you want to work with VistaDB in VS design-time, you need to add the connector to the designer plugins, as described in the readme.txt:
    wrote:
    1) register using the FastReport IDE
    - open the report designer;
    - go "View|Options..." menu;
    - on the "Plugins" tab, add the FastReport.VistaDB.dll;
    - restart FastReport. If you are working in the Visual Studio IDE, restart
    it as well;

    2) no it's FastReport.Data.VistaDBDataConnection
  • StarkStark Syria
    edited June 2009
    Thank you for your Quick replay ....

    I added the plug in and restart the VS IDE , and the Report , (at the first time)

    but still no luck , I can design my report and VistaDB connection from designer.exe ...

    but not from VS IDE ....



    But I can deal with this ....
    I desing my report at designer.exe and save it . .
    Then I added the saved report to my project as resource string manually ...
    then I call report1.loadfromstring (....)

    I just wanted to tell that .... thats all ....

    no need to bother your self , if it's work ok with you ...

    I am fine ...

    Thank you , so mcuh >

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