IIF

mjgouldinimjgouldini
edited 12:14PM in FastReport 3.0
I have a simple IIF that just will not work. It throws the ") expected" error.

What I think should work: IIF( valueA > valueB, "true", "false")

I have tried:

[IIF( valueA > valueB, "true", "false")]

IIF( valueA > valueB; "true", "false")

[IIF( valueA > valueB; "true", "false")]

Nothing seems to work on this very basic attempt.

HELP!

Michael

Comments

  • gordkgordk St.Catherines On. Canada.
    edited 12:14PM
    it needs to be
    [IIF( (valueA > valueB); "true", "false")]

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