Report.Export raises an exception "The path is not of a legal form" when exporting to stre

Comments

• AlexTZ

  January 2009 edited 12:05PM

  Hello,
  
  HTML export output can't be saved to a stream because it may contain several files (.html file per each report page + image files).
• Trebor

  January 2009 edited 12:05PM

  AlexTZ wrote: »

  Hello,
  
  HTML export output can't be saved to a stream because it may contain several files (.html file per each report page + image files).

  
  Thanks,
  
  I changed the HTML export filter with RTF filter, but now I'm facing another error
  ( "Cannot start process because a file name has not been provided.") when exporting to stream:
  
  Report rep = new Report();
  rep.Load(Request.PhysicalApplicationPath + "MyRep.frx");
  rep.RegisterData(... some data ... );
  rep.Prepare();
  FastReport.Export.RichText.RTFExport export = new FastReport.Export.RichText.RTFExport();
  MemoryStream St = new MemoryStream();
  rep.Export(export, St); // this line causes the error "Cannot start process because a file name has not been provided."
  
  Any help ?
  
  
• AlexTZ

  January 2009 edited 12:05PM

  Set export.OpenAfterExport to false. I will fix this later.
• Trebor

  January 2009 edited 12:05PM

  AlexTZ wrote: »

  Set export.OpenAfterExport to false. I will fix this later.

  
  Thanks,
  
  Now, the stream length is OK ( the same with the file length when exporting to file ), but the stream content is emtpy .
  ( When I read the stream content into byte array, the whole array is filled with bytes with value = 0 )
  
  FastReport.Export.RichText.RTFExport export = new FastReport.Export.RichText.RTFExport();
  export.OpenAfterExport = false;
  
  MemoryStream St = new MemoryStream();
  rep.Export(export, St);
  
  Byte[] buffer = new Byte[St.Length];
  St.Read(buffer, 0, (int)St.Length); // all the elements of the buffer are bytes with value = 0
  
  
  Any help ?
  
  
  
• AlexTZ

  January 2009 edited 12:05PM

  Set St.Position to 0 before read from stream.